(2/5)t^2-(5/2)=0

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Solution for (2/5)t^2-(5/2)=0 equation: 


t in (-oo:+oo)

(2/5)*t^2-(5/2) = 0

(2/5)*t^2-5/2 = 0

2/5*t^2 = 5/2 // : 2/5

t^2 = 25/4

t^2 = 25/4 // ^ 1/2

abs(t) = 5/2

t = 5/2 or t = -5/2

t in { 5/2, -5/2 }

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